q-analog of rising powers

The Endeavour 2024-07-23

The previous post looked at the probability that a random n by n matrix over a finite field of order q is invertible. This works out to be

\prod_{i=1}^n \left(1 - \frac{1}{q^i}\right)

This function of q and n comes up in other contexts as well and has a name that we will get to shortly.

Pochhammer symbols

Leo August Pochhammer (1841–1920) defined the kth rising power of x by

(x)_k = x(x + 1)(x + 2)\cdots(x + k - 1)

Rising and falling powers come up naturally in combinatorics, finite difference analogs of calculus, and in the definition of hypergeometric functions.

q-Pochhammer symbols

The q-analog of the Pochhammer symbol is defined as

(a;q)_n = \prod_{k=0}^{n-1} (1-aq^k)=(1-a)(1-aq)(1-aq^2)\cdots(1-aq^{n-1})

Like the Pochhammer symbol, the q-Pochhammer symbol also comes up in combinatorics.

In general, q-analogs of various concepts are generalizations that reduce to the original concept in some sort of limit as q goes to 1. The relationship between the q-Pochhammer symbol and the Pochhammer symbol is

\lim_{q\to 1} \frac{(q^x;q)_n}{(1-q)^n} = (x)_n For a simpler introduction to q-analogs, see this post on q-factorial and q-binomial coefficients.

Back to our probability problem

The motivation for this post was to give a name to the function that gives probability a random n by n matrix over a finite field of order q is invertible. In the notation above, this function is (1/q; 1/q)n.

There’s a confusing notational coincidence here. The number of elements in a finite field is usually denoted by q. The q in q-analogs such as the q-Pochhammer symbol has absolute value less than 1. It’s a coincidence that they both use the letter q, and the q in our application of q-Pochhammer symbols is the reciprocal of the q representing the order of a finite field.

I mentioned in the previous post that the probability of the matrix being invertible is a decreasing function of n. This probability decreases to a positive limit, varying with the value of q. This limit is (1/q; 1/q). Here the subscript ∞ denotes that we take the limit in (1/q; 1/q)n as n goes to infinity. There’s no problem here because the infinite product converges.

Mathematica and plotting

The q-Pochhammer symbol (a; q)n is implemented in Mathematica as QPochhammer[a, q, n] and the special case (q; q) is implemented as QPochhammer[q]. We can use the latter to make the following plot.

Plot[QPochhammer[q], {q, -1, 1}]

Recall that the q in our motivating application is the reciprocal of the q in the q-Pochhhammer symbol. This says for large fields, the limiting probability that an n by n matrix is invertible as n increases is near 1, but that for smaller fields the limiting probability is also smaller. For q = 2, the probability is 0.288788.

Plot[QPochhammer[1/q], {q, 2, 100}, PlotRange -> All]

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